Integrand size = 19, antiderivative size = 400 \[ \int x \sqrt {a+b \sqrt {c x^3}} \, dx=\frac {4}{11} x^2 \sqrt {a+b \sqrt {c x^3}}+\frac {12 a x^2 \sqrt {a+b \sqrt {c x^3}}}{55 b \sqrt {c x^3}}-\frac {8\ 3^{3/4} \sqrt {2+\sqrt {3}} a^2 \left (\sqrt [3]{a}+\frac {\sqrt [3]{b} c^{2/3} x^2}{\sqrt {c x^3}}\right ) \sqrt {\frac {a^{2/3}+b^{2/3} \sqrt [3]{c} x-\frac {\sqrt [3]{a} \sqrt [3]{b} c^{2/3} x^2}{\sqrt {c x^3}}}{\left (\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\frac {\sqrt [3]{b} c^{2/3} x^2}{\sqrt {c x^3}}\right )^2}} \operatorname {EllipticF}\left (\arcsin \left (\frac {\left (1-\sqrt {3}\right ) \sqrt [3]{a}+\frac {\sqrt [3]{b} c^{2/3} x^2}{\sqrt {c x^3}}}{\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\frac {\sqrt [3]{b} c^{2/3} x^2}{\sqrt {c x^3}}}\right ),-7-4 \sqrt {3}\right )}{55 b^{4/3} c^{2/3} \sqrt {\frac {\sqrt [3]{a} \left (\sqrt [3]{a}+\frac {\sqrt [3]{b} c^{2/3} x^2}{\sqrt {c x^3}}\right )}{\left (\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\frac {\sqrt [3]{b} c^{2/3} x^2}{\sqrt {c x^3}}\right )^2}} \sqrt {a+b \sqrt {c x^3}}} \]
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Time = 0.20 (sec) , antiderivative size = 400, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.263, Rules used = {376, 348, 285, 327, 224} \[ \int x \sqrt {a+b \sqrt {c x^3}} \, dx=-\frac {8\ 3^{3/4} \sqrt {2+\sqrt {3}} a^2 \left (\sqrt [3]{a}+\frac {\sqrt [3]{b} c^{2/3} x^2}{\sqrt {c x^3}}\right ) \sqrt {\frac {a^{2/3}-\frac {\sqrt [3]{a} \sqrt [3]{b} c^{2/3} x^2}{\sqrt {c x^3}}+b^{2/3} \sqrt [3]{c} x}{\left (\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\frac {\sqrt [3]{b} c^{2/3} x^2}{\sqrt {c x^3}}\right )^2}} \operatorname {EllipticF}\left (\arcsin \left (\frac {\frac {\sqrt [3]{b} c^{2/3} x^2}{\sqrt {c x^3}}+\left (1-\sqrt {3}\right ) \sqrt [3]{a}}{\frac {\sqrt [3]{b} c^{2/3} x^2}{\sqrt {c x^3}}+\left (1+\sqrt {3}\right ) \sqrt [3]{a}}\right ),-7-4 \sqrt {3}\right )}{55 b^{4/3} c^{2/3} \sqrt {\frac {\sqrt [3]{a} \left (\sqrt [3]{a}+\frac {\sqrt [3]{b} c^{2/3} x^2}{\sqrt {c x^3}}\right )}{\left (\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\frac {\sqrt [3]{b} c^{2/3} x^2}{\sqrt {c x^3}}\right )^2}} \sqrt {a+b \sqrt {c x^3}}}+\frac {12 a x^2 \sqrt {a+b \sqrt {c x^3}}}{55 b \sqrt {c x^3}}+\frac {4}{11} x^2 \sqrt {a+b \sqrt {c x^3}} \]
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Rule 224
Rule 285
Rule 327
Rule 348
Rule 376
Rubi steps \begin{align*} \text {integral}& = \text {Subst}\left (\int x \sqrt {a+b \sqrt {c} x^{3/2}} \, dx,\sqrt {x},\frac {\sqrt {c x^3}}{\sqrt {c} x}\right ) \\ & = \text {Subst}\left (2 \text {Subst}\left (\int x^3 \sqrt {a+b \sqrt {c} x^3} \, dx,x,\sqrt {x}\right ),\sqrt {x},\frac {\sqrt {c x^3}}{\sqrt {c} x}\right ) \\ & = \frac {4}{11} x^2 \sqrt {a+b \sqrt {c x^3}}+\text {Subst}\left (\frac {1}{11} (6 a) \text {Subst}\left (\int \frac {x^3}{\sqrt {a+b \sqrt {c} x^3}} \, dx,x,\sqrt {x}\right ),\sqrt {x},\frac {\sqrt {c x^3}}{\sqrt {c} x}\right ) \\ & = \frac {4}{11} x^2 \sqrt {a+b \sqrt {c x^3}}+\frac {12 a x^2 \sqrt {a+b \sqrt {c x^3}}}{55 b \sqrt {c x^3}}-\text {Subst}\left (\frac {\left (12 a^2\right ) \text {Subst}\left (\int \frac {1}{\sqrt {a+b \sqrt {c} x^3}} \, dx,x,\sqrt {x}\right )}{55 b \sqrt {c}},\sqrt {x},\frac {\sqrt {c x^3}}{\sqrt {c} x}\right ) \\ & = \frac {4}{11} x^2 \sqrt {a+b \sqrt {c x^3}}+\frac {12 a x^2 \sqrt {a+b \sqrt {c x^3}}}{55 b \sqrt {c x^3}}-\frac {8\ 3^{3/4} \sqrt {2+\sqrt {3}} a^2 \left (\sqrt [3]{a}+\frac {\sqrt [3]{b} c^{2/3} x^2}{\sqrt {c x^3}}\right ) \sqrt {\frac {a^{2/3}+b^{2/3} \sqrt [3]{c} x-\frac {\sqrt [3]{a} \sqrt [3]{b} c^{2/3} x^2}{\sqrt {c x^3}}}{\left (\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\frac {\sqrt [3]{b} c^{2/3} x^2}{\sqrt {c x^3}}\right )^2}} F\left (\sin ^{-1}\left (\frac {\left (1-\sqrt {3}\right ) \sqrt [3]{a}+\frac {\sqrt [3]{b} c^{2/3} x^2}{\sqrt {c x^3}}}{\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\frac {\sqrt [3]{b} c^{2/3} x^2}{\sqrt {c x^3}}}\right )|-7-4 \sqrt {3}\right )}{55 b^{4/3} c^{2/3} \sqrt {\frac {\sqrt [3]{a} \left (\sqrt [3]{a}+\frac {\sqrt [3]{b} c^{2/3} x^2}{\sqrt {c x^3}}\right )}{\left (\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\frac {\sqrt [3]{b} c^{2/3} x^2}{\sqrt {c x^3}}\right )^2}} \sqrt {a+b \sqrt {c x^3}}} \\ \end{align*}
\[ \int x \sqrt {a+b \sqrt {c x^3}} \, dx=\int x \sqrt {a+b \sqrt {c x^3}} \, dx \]
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Time = 5.47 (sec) , antiderivative size = 350, normalized size of antiderivative = 0.88
method | result | size |
default | \(\frac {\frac {4 i a^{2} \sqrt {3}\, \left (-a \,b^{2} c \right )^{\frac {1}{3}} \sqrt {2}\, \sqrt {-\frac {i \left (i \sqrt {3}\, x \left (-a \,b^{2} c \right )^{\frac {1}{3}}-2 b \sqrt {c \,x^{3}}-x \left (-a \,b^{2} c \right )^{\frac {1}{3}}\right ) \sqrt {3}}{x \left (-a \,b^{2} c \right )^{\frac {1}{3}}}}\, \sqrt {\frac {b \sqrt {c \,x^{3}}-x \left (-a \,b^{2} c \right )^{\frac {1}{3}}}{x \left (-a \,b^{2} c \right )^{\frac {1}{3}} \left (i \sqrt {3}-3\right )}}\, \sqrt {-\frac {i \left (i \sqrt {3}\, x \left (-a \,b^{2} c \right )^{\frac {1}{3}}+2 b \sqrt {c \,x^{3}}+x \left (-a \,b^{2} c \right )^{\frac {1}{3}}\right ) \sqrt {3}}{x \left (-a \,b^{2} c \right )^{\frac {1}{3}}}}\, F\left (\frac {\sqrt {3}\, \sqrt {2}\, \sqrt {-\frac {i \left (i \sqrt {3}\, x \left (-a \,b^{2} c \right )^{\frac {1}{3}}-2 b \sqrt {c \,x^{3}}-x \left (-a \,b^{2} c \right )^{\frac {1}{3}}\right ) \sqrt {3}}{x \left (-a \,b^{2} c \right )^{\frac {1}{3}}}}}{6}, \sqrt {2}\, \sqrt {\frac {i \sqrt {3}}{i \sqrt {3}-3}}\right ) \sqrt {c \,x^{3}}}{55}+\frac {4 c^{2} x^{5} b^{3}}{11}+\frac {32 \sqrt {c \,x^{3}}\, a \,b^{2} c \,x^{2}}{55}+\frac {12 a^{2} b c \,x^{2}}{55}}{c \,b^{2} \sqrt {c \,x^{3}}\, \sqrt {a +b \sqrt {c \,x^{3}}}}\) | \(350\) |
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\[ \int x \sqrt {a+b \sqrt {c x^3}} \, dx=\int { \sqrt {\sqrt {c x^{3}} b + a} x \,d x } \]
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\[ \int x \sqrt {a+b \sqrt {c x^3}} \, dx=\int x \sqrt {a + b \sqrt {c x^{3}}}\, dx \]
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\[ \int x \sqrt {a+b \sqrt {c x^3}} \, dx=\int { \sqrt {\sqrt {c x^{3}} b + a} x \,d x } \]
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\[ \int x \sqrt {a+b \sqrt {c x^3}} \, dx=\int { \sqrt {\sqrt {c x^{3}} b + a} x \,d x } \]
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Timed out. \[ \int x \sqrt {a+b \sqrt {c x^3}} \, dx=\int x\,\sqrt {a+b\,\sqrt {c\,x^3}} \,d x \]
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